NBT Mathematics: Functions and Graphs Flashcards
7 cards from real NBT practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 NBT Mathematics: Functions and Graphs flashcards as text
The graph of y = 2x − 4 is shifted 3 units upward. What is the new equation?
Answer: y = 2x − 1
Adding 3 to the function: y = 2x − 4 + 3 = 2x − 1.
A table of values shows: x = 0 → y = 1, x = 1 → y = 3, x = 2 → y = 9, x = 3 → y = 27. What is the function?
Answer: y = 3^x
Each y is 3 multiplied by the previous y (×3 ratio), indicating y = 3^x.
The parabola y = x² + bx + 9 has a double root. What is the value of b?
Answer: b = ±6
Double root ↔ discriminant = 0: b² − 4(1)(9) = 0 → b² = 36 → b = ±6.
Which of these functions is ODD (i.e., f(−x) = −f(x))?
Answer: f(x) = x³
f(−x) = (−x)³ = −x³ = −f(x), so x³ is an odd function.
The graph of f(x) is given. From the graph, f(x) > 0 for x ∈ (−∞, −2) ∪ (3, ∞) and f(x) < 0 for x ∈ (−2, 3). What are the roots of f?
Answer: x = −2 and x = 3
The function changes sign at x = −2 and x = 3 — these are the x-intercepts (roots).
For the function f(x) = |x − 2|, what is f(−1)?
Answer: 3
f(−1) = |−1 − 2| = |−3| = 3.
The straight lines y = 2x + 1 and y = 2x − 3 are:
Answer: Parallel
Both lines have gradient 2 but different y-intercepts, so they are parallel.