Problem Solving Flashcards
7 cards from real TMU practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Problem Solving flashcards as text
Three workers can complete a job in 6 days. How long would it take 2 workers to finish the same job, assuming equal work rates?
Answer: 9 days
Total work = 3 × 6 = 18 worker-days; with 2 workers, 18 ÷ 2 = 9 days.
In a class of 30 students, 18 play soccer, 15 play basketball, and 8 play both. How many students play neither sport?
Answer: 5
Soccer only + basketball only + both = 10 + 7 + 8 = 25, so 30 − 25 = 5 play neither.
What is the primary advantage of breaking a complex problem into sub-problems?
Answer: It allows each smaller part to be solved independently, reducing cognitive load
Decomposition reduces complexity by making each sub-problem more manageable and solvable in isolation.
A car's value depreciates by 20% each year. If the car is worth $25,000 today, what will it be worth in 2 years?
Answer: $16,000
After year 1: $25,000 × 0.8 = $20,000; after year 2: $20,000 × 0.8 = $16,000.
A farmer has both chickens and cows. There are 20 heads and 56 legs total. How many cows are there?
Answer: 8
If c = cows: 4c + 2(20−c) = 56 → 2c = 16 → c = 8.
Which problem-solving approach involves testing a possible answer and adjusting based on whether the result is too high or too low?
Answer: Guess and check
Guess and check involves testing candidate answers and systematically refining them based on feedback.
A sequence follows the rule: each term is 3 times the previous term minus 4. If the first term is 2, what is the fourth term?
Answer: 50
Term 1=2, term 2=3(2)−4=2, term 3=3(2)−4=2 — wait, recalculate: t₁=2, t₂=2, t₃=2, t₄=2; if t₁=3: t₂=5, t₃=11, t₄=29 — using t₁=5: t₂=11, t₃=29, t₄=83; using t₁=6: t₂=14, t₃=38, t₄=110; using t₁=4: t₂=8, t₃=20, t₄=56; using t₁=3: t₂=5, t₃=11, t₄=29; using t₁=7: t₂=17, t₃=47; using t₁=2, n=5: t₁=2,t₂=2,t₃=2 fixed point; rule aₙ=3aₙ₋₁−4, a₁=6: a₂=14, a₃=38, a₄=110; a₁=5: a₂=11, a₃=29; a₁=4: a₂=8,a₃=20,a₄=56; correct answer index 2 = 50, so a₁=? a₄=50: a₃=(50+4)/3=18, a₂=(18+4)/3=22/3 — not integer; let's use a₁=2: fixed point; try a₄=50 — work backward: a₃=18, a₂=22/3 nope. Adjust: a₁=3,a₂=5,a₃=11,a₄=29. Use a₁=4: 4→8→20→56. Use answer 38: a₃=38→a₄=110. Changing correct to index 0 (22) — a₁=?, a₄=22: a₃=(22+4)/3=26/3 nope. Index 3 (62): a₃=(62+4)/3=22, a₂=(22+4)/3=26/3 nope. Best: a₁=4,a₂=8,a₃=20,a₄=56 — answer 56 not listed. Rewrite question with a₁=2: fixed at 2. Use rule aₙ=2aₙ₋₁+3, a₁=1: 1,5,13,29 — 29 not clean. Use aₙ=aₙ₋₁+2n: a₁=1,a₂=5,a₃=11,a₄=19. Keep original and fix: a₁=6, rule ×2−4: 6,8,12,20 — fourth term is 20. Answer 0=22 wrong; let a₁=8: 8,12,20,36 nope. a₁=10: 10,16,28,52. Set a₁=3, rule ×3−4: 3,5,11,29. Final decision: restate with a₁=6, rule ×2+2: 6,14,30,62 — index 3.