Electrical Knowledge Flashcards
6 cards from real Ramsay Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 6 Electrical Knowledge flashcards as text
A 480V, 3-phase motor draws 18A per phase at full load with a power factor of 0.82 lagging. What is the approximate true power (kW) consumed by the motor?
Answer: 12.2 kW
True power P = √3 × V × I × PF = 1.732 × 480 × 18 × 0.82 ≈ 12,237W ≈ 12.2 kW. Many candidates confuse apparent power (kVA) with true power (kW) — multiplying by the power factor is essential for 3-phase calculations.
A technician measures voltage drop across a 150-foot run of 12 AWG copper wire (resistance ≈ 1.98 Ω per 1,000 ft) carrying 15A. What is the approximate one-way voltage drop?
Answer: 2.97V
Resistance of 150 ft = (150/1000) × 1.98 = 0.297 Ω. Voltage drop = I × R = 15 × 0.297 ≈ 2.97V. The round-trip (total conductor length) would be 300 ft, but the question asks for one-way drop. Confusing one-way vs. round-trip is a common error.
Which wiring method is MOST appropriate when installing conductors in a Class I, Division 1 hazardous location where flammable vapors may be present under normal operating conditions?
Answer: Rigid metal conduit (RMC) with threaded fittings
NEC Article 501 requires threaded rigid metal conduit or threaded steel intermediate metal conduit in Class I, Division 1 locations. EMT set-screw fittings are not explosionproof, FMC is only permitted for short equipment connections under strict conditions, and standard MC cable is not suitable for Division 1 areas.
Two capacitors — 40 µF and 60 µF — are connected in series across a 120V supply. What is the voltage across the 40 µF capacitor?
Answer: 72V
In series, capacitors share the same charge (Q). Total capacitance = (40×60)/(40+60) = 24 µF. Q = C_total × V = 24 µF × 120V = 2,880 µC. V across 40 µF = Q / C = 2,880 / 40 = 72V. The smaller capacitor holds MORE voltage — the opposite of series resistors.
A transformer nameplate reads: 10 kVA, 2400V primary, 240V secondary. The secondary winding has 80 turns. How many turns does the primary winding have?
Answer: 800
The turns ratio equals the voltage ratio: N_primary / N_secondary = V_primary / V_secondary → N_primary / 80 = 2400 / 240 = 10 → N_primary = 800 turns. The kVA rating is relevant only for current calculations, not turns.
A technician uses a clamp meter to measure current in a 3-phase, 4-wire system and clamps around ALL four conductors simultaneously (three hots and the neutral). The meter reads 2.3A. What does this most likely indicate?
Answer: A ground fault or leakage current to earth
In a perfectly balanced 3-phase, 4-wire system the vector sum of all four conductors (3 phase + neutral) should be zero, giving a 0A reading. A non-zero reading indicates current is returning via an unintended path — i.e., a ground fault or leakage current. This technique is a standard ground-fault detection method.