Python Control Flow: Conditional Statements Questions and Answers

Question 1

What is the output of the following Python code snippet?

```python
temperature = 25
if temperature > 30:
    print("Hot")
elif temperature > 20:
    print("Warm")
else:
    print("Cold")
```

Accepted Answer

Warm

Answer

Hot

Answer

Cold

Answer

No output will be generated.

Question 2

Which of the following code snippets correctly uses the ternary operator to assign 'Adult' to the `status` variable if `age` is 18 or greater, and 'Minor' otherwise?

Accepted Answer

status = 'Adult' if age >= 18 else 'Minor'

Answer

status = age >= 18 ? 'Adult' : 'Minor'

Answer

status = if age >= 18: 'Adult' else: 'Minor'

Answer

status = 'Adult' else 'Minor' if age >= 18

Question 3

A programmer wants to write a script to check for a specific error condition. The program should print 'Error Found' only if `error_code` is not 0 AND `is_critical` is True. Which of the following conditional statements accomplishes this?

Accepted Answer

if error_code != 0 and is_critical:
    print("Error Found")

Answer

if error_code != 0 or is_critical == True:
    print("Error Found")

Answer

if not (error_code == 0 and is_critical == True):
    print("Error Found")

Answer

if error_code == 0 and is_critical == False:
    print("Error Found")

Question 4

What will be printed to the console when the following Python code is executed?

```python
x = 10
y = 20

if x > 5:
    print("A")
    if y > 15:
        print("B")
elif x > 8:
    print("C")
else:
    print("D")
```

Accepted Answer

A
B

Answer

A

Answer

C

Answer

A
C

Question 5

In Python, what is the primary purpose of the `elif` keyword in a conditional statement?

Accepted Answer

To check multiple distinct conditions in sequence without excessive nesting.

Answer

To execute a block of code if the initial `if` condition is false.

Answer

To check an additional condition only if all previous `if` and `elif` conditions were false.

Answer

To create a nested level of conditional logic inside an `if` block.

Question 6

Consider the following code intended to classify a number. What is a potential issue with its logic?

```python
num = 0

if num >= 0:
    print("Positive or Zero")
if num == 0:
    print("Zero")
else:
    print("Negative")
```

Accepted Answer

It will print two lines for an input of 0.

Answer

The code will raise a SyntaxError.

Answer

The `else` statement will never be reached.

Answer

It will incorrectly print "Negative" for an input of 0.