Probability and Combinatorics Flashcards
6 cards from real IMSA practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 6 Probability and Combinatorics flashcards as text
How many ways can you choose 3 students from a class of 10 (order doesn't matter)?
Answer: 120
C(10,3) = 10!/(3! × 7!) = (10 × 9 × 8)/(3 × 2 × 1) = 120.
Two dice are rolled. What is the probability that both show a 6?
Answer: 1/36
P(6) × P(6) = (1/6) × (1/6) = 1/36.
A spinner has 8 equal sections numbered 1−8. What is the probability of landing on an odd number?
Answer: 1/2
The odd numbers are 1, 3, 5, 7 (four values), so P = 4/8 = 1/2.
How many different 3-letter arrangements can be made from the letters A, B, C, D (no repetition)?
Answer: 24
This is a permutation: P(4,3) = 4 × 3 × 2 = 24.
Events A and B are mutually exclusive. P(A) = 0.3 and P(B) = 0.4. What is P(A or B)?
Answer: 0.7
For mutually exclusive events, P(A or B) = P(A) + P(B) = 0.3 + 0.4 = 0.7.
A card is drawn from a standard deck. What is the probability it is a heart or a king?
Answer: 4/13
P(heart) = 13/52, P(king) = 4/52, P(king of hearts) = 1/52; P(heart or king) = 16/52 = 4/13.