Subnetting Flashcards
7 cards from real ICND1 practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Subnetting flashcards as text
You need to divide 192.168.50.0/24 into subnets supporting 60 hosts each. Which mask should you use?
Answer: /26
A /26 provides 62 usable hosts (64 - 2), which is the smallest mask that supports 60 hosts.
What is the network address of the subnet containing 172.16.35.200/20?
Answer: 172.16.32.0
/20 has a block size of 16 in the third octet; 35 falls in the 32–47 range, so the network is 172.16.32.0.
Which of the following addresses is a valid host in the subnet 10.0.0.128/25?
Answer: 10.0.0.200
The subnet 10.0.0.128/25 covers 10.0.0.128–10.0.0.255; only 10.0.0.200 is a valid host (not the broadcast .255).
How many bits must be borrowed from the host portion of a Class B address to create 100 subnets?
Answer: 7
2^7 = 128 ≥ 100 and 2^6 = 64 < 100, so 7 bits must be borrowed.
What is the broadcast address of the subnet 10.20.30.64/27?
Answer: 10.20.30.95
A /27 has a block size of 32; the subnet starting at .64 ends at .64 + 31 = .95, which is the broadcast.
Which decimal value does the binary octet 11111000 represent in a subnet mask?
Answer: 248
11111000 = 128+64+32+16+8 = 248.
A /24 network is subnetted into /28 subnets. How many hosts can each subnet support?
Answer: 14
A /28 leaves 4 host bits; 2^4 - 2 = 14 usable host addresses per subnet.