Abstract Reasoning Matrices Flashcards
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Read the first 7 Abstract Reasoning Matrices flashcards as text
A matrix pattern alternates the count of shapes: step 1 = 4 shapes, step 2 = 6 shapes, step 3 = 4 shapes, step 4 = 6 shapes. How many shapes appear in step 7?
Answer: 4
Odd-numbered steps always have 4 shapes; step 7 is odd, so it has 4 shapes.
A 3×3 matrix assigns each cell a letter based on (row number + column number), where A=1, B=2, etc. What letter belongs in row 2, column 4?
Answer: F
Row 2 + column 4 = 6, and the 6th letter of the alphabet is F.
In a matrix, each row applies a 'subtract inner shape' rule moving left to right. Column 1 has a circle with a triangle inside; column 2 has a circle with a square inside; column 3 has a circle only. Row 3, col 1 has a pentagon with a star inside. What is in row 3, col 3?
Answer: Pentagon only
Column 3 always removes the inner shape, leaving only the outer pentagon.
A matrix rotates a shape 45° clockwise with each step. A downward-pointing triangle (▽) is in position 1. What orientation appears in position 9?
Answer: Downward-pointing triangle (▽)
Eight 45° rotations complete a full 360° cycle, so position 9 = position 1, which is ▽.
A matrix shows figures where each row adds one element to a growing pattern: row 1 has a line, row 2 has a line and a circle, row 3 has a line, a circle, and a square. What does row 5 contain?
Answer: Line, circle, square, triangle, pentagon
Each row adds the next shape in the sequence; row 5 adds a pentagon to the four elements of row 4.
A 3×3 matrix assigns values so that each row sums to 15 and each column sums to 15 (a magic square). The center cell is 5 and the top-left is 2. What value belongs in the top-right cell?
Answer: 6
In a standard 3×3 magic square with center 5, the top row is 2, 7, 6 — making the top-right cell 6.
A matrix uses a difference rule: each cell equals the difference between the cell above it and the cell to its left. Row 1: 10, 6, 4. Row 2: 8, ?, 2. What is the missing value?
Answer: 2
The cell = cell above (6) − cell to its left (8) using absolute difference: |6 − 8| = 2.