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Pulleys, Gears, and Levers Flashcards

7 cards from real FCTC practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Pulleys, Gears, and Levers flashcards as text
  1. A pulley system requires a worker to pull 12 feet of rope to raise a load 3 feet. What is the mechanical advantage of the system?

    Answer: 4

    Mechanical advantage = rope pulled ÷ load distance = 12 ÷ 3 = 4.

  2. A nutcracker is an example of which class of lever?

    Answer: Second-class

    A nutcracker is a second-class lever — the fulcrum is at the hinge end, effort is at the handles, and the nut (load) is in the middle.

  3. In a gear train, which gear arrangement is used to convert rotational motion into linear (straight-line) motion?

    Answer: Rack and pinion

    A rack and pinion system converts the rotational motion of a circular gear (pinion) into the linear motion of a flat toothed bar (rack).

  4. If friction is present in a pulley system, how does it affect the actual mechanical advantage compared to the theoretical value?

    Answer: Actual MA is lower than theoretical

    Friction reduces the actual mechanical advantage because some input force is lost overcoming friction, meaning more effort is needed than theory predicts.

  5. A lever has a load of 300 lbs placed 2 feet from the fulcrum. How far from the fulcrum must a 100-lb effort be applied to balance the lever?

    Answer: 6 feet

    Using the lever principle: Load × Load arm = Effort × Effort arm → 300 × 2 = 100 × x → x = 6 feet.

  6. Which pulley arrangement provides NO mechanical advantage but is still useful in practical applications?

    Answer: Fixed pulley

    A single fixed pulley has a mechanical advantage of 1 (no force reduction) but changes the direction of force, which is practically useful.

  7. In a gear train where the driver has 30 teeth and the driven gear has 15 teeth, the output shaft rotates at what speed relative to the input?

    Answer: Twice the input speed

    Gear ratio = driver teeth / driven teeth = 30/15 = 2, so the driven gear spins twice as fast as the driver.