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FCTC Mechanical Reasoning Principles Questions and Answers Flashcards

7 cards from real FCTC practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 FCTC Mechanical Reasoning Principles Questions and Answers flashcards as text
  1. A compound pulley system has 4 rope segments supporting the load. What is its mechanical advantage?

    Answer: 4

    In a pulley system, mechanical advantage equals the number of rope segments supporting the movable block, which is 4.

  2. An object weighing 80 lbs is placed on a frictionless inclined plane angled at 30°. What force parallel to the ramp is needed to hold the object in place?

    Answer: 40 lbs

    The force needed equals weight × sin(30°) = 80 × 0.5 = 40 lbs.

  3. Gear A (8 teeth) drives Gear B (16 teeth), which is on the same shaft as Gear C (8 teeth), which drives Gear D (32 teeth). What is the overall gear ratio from A to D?

    Answer: 8:1

    Ratio A to B = 2:1; ratio C to D = 4:1; total ratio = 2 × 4 = 8:1 speed reduction.

  4. A refrigerator weighing 300 lbs is rolled up a 15-foot ramp to a platform 5 feet high. What is the ideal mechanical advantage of the ramp?

    Answer: 3

    MA = ramp length ÷ ramp height = 15 ÷ 5 = 3.

  5. What principle explains why a wider tire provides more traction on soft ground than a narrow tire of the same weight?

    Answer: Greater surface area reduces pressure per square inch

    Pressure = force ÷ area; spreading the same weight over a larger area reduces pressure per square inch, preventing the tire from sinking into soft terrain.

  6. A firefighter pulls a rope over a fixed pulley attached to the ceiling to raise a 180 lb victim. How much force must the firefighter exert on the rope (ignoring friction)?

    Answer: 180 lbs

    A single fixed pulley only changes direction of force and provides no mechanical advantage, so the effort equals the load: 180 lbs.

  7. Two pistons in a hydraulic brake system: the master cylinder has a 1 sq in area and the caliper piston has a 4 sq in area. If the driver applies 25 lbs to the master piston, what clamping force is produced at the caliper?

    Answer: 100 lbs

    Hydraulic pressure = 25 ÷ 1 = 25 psi; clamping force = 25 psi × 4 sq in = 100 lbs.