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Soil Mechanics and Lab Testing Flashcards

7 cards from real Civil Engineering PE practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Soil Mechanics and Lab Testing flashcards as text
  1. A soil has a shrinkage limit (SL) of 12%, plastic limit (PL) of 22%, and liquid limit (LL) of 48%. What is the shrinkage ratio if the soil volume at the shrinkage limit is 24.5 cm³ and dry mass is 36 g, using γw = 1 g/cm³?

    Answer: 1.47

    Shrinkage ratio SR = Ms/(Vs × γw) = 36/(24.5 × 1.0) = 1.47 g/cm³.

  2. In geotechnical engineering, what is the significance of the preconsolidation pressure (σ'c) determined from a consolidation test?

    Answer: It marks the stress boundary between recompression and virgin compression behavior

    Preconsolidation pressure separates the lightly (elastic) recompression range from the normally consolidated (plastic) compression range on the e-log p curve.

  3. A saturated soil specimen in an unconsolidated-undrained (UU) triaxial test shows zero friction angle (φ = 0). If the unconfined compressive strength (qu) is 80 kPa, what is the undrained shear strength (su)?

    Answer: 40 kPa

    For φu = 0, su = cu = qu/2 = 80/2 = 40 kPa; the Mohr circle radius equals the shear strength.

  4. A sand has a maximum void ratio of 0.82 and minimum void ratio of 0.45. A field sample has a void ratio of 0.60. What is the relative density (Dr)?

    Answer: 59.5%

    Dr = (emax − e)/(emax − emin) × 100 = (0.82 − 0.60)/(0.82 − 0.45) × 100 = 0.22/0.37 × 100 ≈ 59.5%.

  5. Which index property best distinguishes between a silty soil (ML or MH) and a clayey soil (CL or CH) in the USCS classification system?

    Answer: Position relative to the A-line on the plasticity chart

    The A-line (U = 0.73(LL − 20)) on the Casagrande plasticity chart separates clays (above) from silts and organic soils (below).

  6. In a sieve analysis, what percentage of soil passes the No. 200 sieve if the retained amounts are: No. 4 = 15 g, No. 10 = 25 g, No. 40 = 35 g, No. 200 = 45 g, and pan = 30 g from a total dry mass of 150 g?

    Answer: 20%

    Mass passing No. 200 = pan fraction = 30 g; percent passing = 30/150 × 100 = 20%.

  7. A compaction curve shows optimum moisture content (OMC) at 15%. A contractor compacts soil at 12% moisture. Compared to the dry side of optimum, what is the most significant engineering implication?

    Answer: Higher strength and stiffness but more brittle and susceptible to collapse upon wetting

    Compaction dry of optimum produces a flocculated structure with higher strength but more collapse potential when saturated, compared to the dispersed, more ductile wet-side structure.