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Civil Engineering Theory of Structure Flashcards

7 cards from real Civil Engineering PE practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Civil Engineering Theory of Structure flashcards as text
  1. In plastic analysis, a beam mechanism forms when the number of plastic hinges equals:

    Answer: The degree of static indeterminacy plus one

    For a beam to form a mechanism, the number of plastic hinges must equal the degree of static indeterminacy plus one (n = r + 1).

  2. The flexibility coefficient f_ij represents:

    Answer: The displacement at coordinate i due to a unit force at coordinate j

    Flexibility coefficient f_ij is the displacement (or rotation) at coordinate i caused by a unit force (or moment) applied at coordinate j.

  3. Castigliano's second theorem states that the partial derivative of total strain energy U with respect to a force P_i equals:

    Answer: The deflection at the point and direction of P_i

    Castigliano's second theorem: δ_i = ∂U/∂P_i, giving the displacement in the direction of force P_i at its point of application.

  4. In a continuous beam analyzed by the three-moment equation (Clapeyron's theorem), the equation relates:

    Answer: Moments at three consecutive supports to the applied loads and spans

    The three-moment equation (Clapeyron's) relates the bending moments at three consecutive supports M_A, M_B, M_C in terms of span lengths, loads, and EI values.

  5. The shape factor (f = Z/S) for a solid circular cross-section is approximately:

    Answer: 1.5

    For a solid circular section, the shape factor f = Z/S = (4r³/3)/(πr³/4) = 16/(3π) ≈ 1.70; however the most commonly cited rounded value is 1.70, making 1.7 correct.

  6. An arch is efficient for carrying loads primarily because:

    Answer: It converts vertical loads into axial compression with minimal bending

    A properly shaped arch converts applied vertical loads into predominantly axial compression along its axis, minimizing bending and using material efficiently.

  7. The distribution factor (DF) at a joint in the moment distribution method for member AB is:

    Answer: K_AB / ΣK at the joint

    The distribution factor for member AB at a joint equals the relative stiffness of that member divided by the sum of stiffnesses of all members meeting at the joint.