Metric & Imperial Conversion Flashcards
7 cards from real CFS practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Metric & Imperial Conversion flashcards as text
What is the tensile stress area of an M12×1.75 bolt in mm²? (Use the formula: As = 0.7854 × (d - 0.9743/n)²)
Answer: 84.3 mm²
For M12×1.75 the standard tensile stress area is 84.3 mm² per ISO 898 tables.
Convert a clamping force of 10,000 N to pound-force (lbf).
Answer: 2,248 lbf
1 N = 0.2248 lbf, so 10,000 N × 0.2248 = 2,248 lbf.
A 3/8-16 UNC bolt has a pitch of how many millimeters?
Answer: 1.588 mm
Pitch = 25.4 ÷ TPI = 25.4 ÷ 16 = 1.5875 mm ≈ 1.588 mm.
An engineer specifies a surface finish of 1.6 μm Ra. What is the approximate equivalent in microinches (μin)?
Answer: 63 μin
1 μm = 39.37 μin, so 1.6 μm × 39.37 ≈ 63 μin.
A nut has a width-across-flats of 19 mm. Which standard inch wrench size is the closest fit?
Answer: 3/4 inch (19.05 mm)
19 mm is nearly identical to 3/4 inch (19.05 mm), making it the closest standard inch wrench.
A fastener's shear strength is listed as 90,000 psi. What is this in ksi?
Answer: 90 ksi
1 ksi = 1,000 psi, so 90,000 psi ÷ 1,000 = 90 ksi.
Convert 8.8 mm bolt grip length to the nearest 1/16 inch increment.
Answer: 11/32 inch (8.73 mm)
8.8 mm ÷ 25.4 = 0.346 in; the nearest 1/16-inch increment is 11/32 in (0.344 in = 8.73 mm).