Application Equipment and Calibration Flashcards
7 cards from real CFA practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 Application Equipment and Calibration flashcards as text
When calibrating a rotary spreader, what does the 'effective spread width' refer to?
Answer: The actual width of coverage that achieves the target application rate
Effective spread width is the working width that delivers the target rate uniformly, which is typically less than the maximum throw distance.
A granular spreader is set to apply 3 lbs per 1,000 sq ft. After calibration, it actually applies 3.6 lbs per 1,000 sq ft. What is the percent error?
Answer: 20%
Percent error = ((3.6 - 3.0) / 3.0) x 100 = 20%.
Which nozzle type is best suited for applications requiring low drift and good canopy penetration?
Answer: Air-induction (venturi) nozzle
Air-induction nozzles produce large air-filled droplets that resist drift while still providing good coverage.
What effect does increasing boom height have on spray pattern overlap from flat-fan nozzles?
Answer: Overlap increases, improving uniformity up to a point
Increasing boom height widens the spray pattern and increases overlap between adjacent nozzles, improving uniformity until excessive height causes drift.
During a jug test, you collect 18.5 oz from a nozzle in 30 seconds. The target output is 20 oz per 30 seconds. What action should you take?
Answer: Accept the output as within 7.5% tolerance
A 7.5% deviation is within the typical +/-10% acceptable tolerance range for nozzle output.
What is the primary reason for conducting a spray system pressure check at the boom rather than at the pump?
Answer: Pressure drops occur through hoses, fittings, and filters between pump and boom
Pressure losses through plumbing components mean boom pressure is lower than pump pressure, and boom pressure determines actual nozzle output.
When calibrating a liquid fertilizer applicator, you travel 200 feet and collect 0.5 gallons from the system. The boom is 20 feet wide. What is the application rate in gallons per acre?
Answer: 54.4 gal/acre
Area covered = (200 ft x 20 ft) / 43,560 = 0.0918 acres; rate = 0.5 / 0.0918 = 54.4 gal/acre.