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Fluid Mechanics Flashcards

7 cards from real BME practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Fluid Mechanics flashcards as text

  1. Reynolds Transport Theorem relates the time rate of change of an extensive property in a:

    Answer: Control volume to a system (material volume)

    Reynolds Transport Theorem converts conservation laws from a Lagrangian system (fixed mass) to an Eulerian control volume formulation.

  2. In pipe network analysis using the Hardy-Cross method, iterations are performed to satisfy:

    Answer: Mass continuity at each node and energy balance around each loop

    Hardy-Cross iterates flow corrections until both nodal flow continuity and loop head-loss balance (∑h_f = 0) are satisfied simultaneously.

  3. The 'no-slip condition' in viscous fluid mechanics states that:

    Answer: The fluid velocity at a solid wall equals the wall velocity

    The no-slip condition requires that viscous fluid immediately adjacent to a solid surface moves at the same velocity as the surface.

  4. Which statement correctly describes the difference between Newtonian and non-Newtonian fluids?

    Answer: Newtonian fluids have constant viscosity; non-Newtonian fluids have viscosity that depends on shear rate

    Newtonian fluids have a linear stress–strain rate relationship (constant μ); non-Newtonian fluids (e.g., blood, paint) exhibit shear-dependent viscosity.

  5. The Buckingham π theorem states that if a physical problem involves n variables and k fundamental dimensions, the number of independent dimensionless groups is:

    Answer: n − k

    Buckingham π theorem: the number of independent dimensionless Π groups equals n (variables) minus k (fundamental dimensions).

  6. In the k-ε turbulence model, the variable ε represents:

    Answer: Rate of dissipation of turbulent kinetic energy

    In the k-ε model, k is turbulent kinetic energy and ε is the rate at which k is dissipated into heat by viscous action.

  7. A manometer uses a U-tube filled with a denser fluid to measure pressure differences. If the manometer fluid is mercury (SG = 13.6) and the height difference is 15 cm, the pressure difference is approximately:

    Answer: 20.0 kPa

    ΔP = ρgh = 13.6×1000×9.81×0.15 ≈ 20,012 Pa ≈ 20.0 kPa.