Practice Test GeeksBluebook SAT Practice Test
← All Bluebook SAT Test Flashcard Decks

Probability and Conditional Probability Flashcards

7 cards from real Bluebook SAT Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 Probability and Conditional Probability flashcards as text

  1. A two-way table records 400 employees by department and satisfaction level. Satisfied Neutral Dissatisfied Engineering 80 40 30 Marketing 60 60 50 Operations 40 20 20 What is the probability a randomly selected employee is from Marketing and Dissatisfied?

    Answer: 1/8

    Marketing & Dissatisfied = 50 out of 400 total; P = 50/400 = 1/8.

  2. P(A) = 0.6 and P(A and B) = 0.18. If A and B are independent, what is P(B)?

    Answer: 0.30

    Since A and B are independent, P(B) = P(A and B)/P(A) = 0.18/0.6 = 0.30.

  3. A box has 3 red, 5 white, and 2 black balls. One ball is drawn and not replaced; then a second is drawn. What is the probability the second ball is red, given the first was white?

    Answer: 1/3

    After removing a white ball, 9 balls remain: 3 red; P = 3/9 = 1/3.

  4. A game wheel has 4 red, 3 blue, and 1 green section. A player spins twice. What is the probability of getting green both times?

    Answer: 1/64

    P(green) = 1/8; for two independent spins, P = (1/8)² = 1/64.

  5. In a class of 25 students, the probability that a randomly chosen student plays guitar is 0.32. What is the expected number of guitar players?

    Answer: 8

    Expected value = 25 × 0.32 = 8.

  6. The two-way table shows 500 people by exercise frequency and BMI category. Normal BMI High BMI Exercise daily 180 70 Rarely exercise 90 160 What fraction of people with a Normal BMI exercise daily?

    Answer: 2/3

    Normal BMI total = 180 + 90 = 270; exercise daily = 180; P = 180/270 = 2/3.

  7. A bag has 7 green and 3 yellow tokens. Two tokens are drawn with replacement. What is the probability of drawing one of each color?

    Answer: 42/100

    P(green then yellow) + P(yellow then green) = (7/10)(3/10) + (3/10)(7/10) = 42/100 = 21/50.