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One-Variable Data: Distributions and Measures of Center and Spread Flashcards

7 cards from real Bluebook SAT Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

Read the first 7 One-Variable Data: Distributions and Measures of Center and Spread flashcards as text

  1. A dataset has values 11, 14, 14, 16, 19, 22. What is the median?

    Answer: 15

    With 6 values, the median is the average of the 3rd and 4th values: (14 + 16) ÷ 2 = 15.

  2. A class of 20 students took a quiz. The mean score was 74. Later, it was discovered that one student's score of 44 was accidentally recorded as 84. What is the corrected mean?

    Answer: 72

    The total sum was incorrectly 74 × 20 = 1480; corrected sum = 1480 − 84 + 44 = 1440; corrected mean = 1440 ÷ 20 = 72.

  3. A survey records the number of pets owned by 8 households: 0, 0, 1, 2, 2, 3, 4, 8. The outlier is 8. Which measure of center is least affected by this outlier?

    Answer: Median

    The median (average of 4th and 5th values = (2+2)/2 = 2) is unaffected by the outlier 8, while the mean is pulled upward.

  4. The heights (in cm) of six plants are 12, 15, 15, 18, 20, and 24. What is the variance of this dataset? (Round to nearest whole number.)

    Answer: 16

    Mean = 104/6 ≈ 17.33; sum of squared deviations ≈ 91.3; variance = 91.3/6 ≈ 15.2, closest to 16.

  5. In a data distribution, the mean is 45 and the median is 52. This indicates the distribution is:

    Answer: Left-skewed

    When the mean is less than the median, the distribution is left-skewed (negatively skewed) because extreme low values pull the mean down.

  6. Data set: 3, 7, 8, 8, 9, 10, 12. Which of the following is true about this dataset?

    Answer: Mode < Median < Mean

    Mode = 8; Median = 8 (4th of 7 values); Mean = (3+7+8+8+9+10+12)/7 = 57/7 ≈ 8.14; so Mode (8) < Median (8) < Mean (8.14).

  7. A normally distributed dataset has a mean of 100 and a standard deviation of 15. Which interval contains approximately 68% of the data?

    Answer: 85 to 115

    The 68-95-99.7 rule states that approximately 68% of data in a normal distribution falls within one standard deviation of the mean: 100 ± 15 = 85 to 115.