One-Variable Data: Distributions and Measures of Center and Spread Flashcards
7 cards from real Bluebook SAT Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 7 One-Variable Data: Distributions and Measures of Center and Spread flashcards as text
A dataset is: 5, 10, 15, 20, 25, 30, 200. Removing the value 200 would most likely:
Answer: Decrease the mean but leave the median relatively unchanged
The outlier 200 greatly inflates the mean; removing it brings the mean down significantly, while the median is resistant to outliers and changes little.
The weights (in pounds) of five packages are 3, 7, 8, 8, and 9. What is the median weight?
Answer: 8
Arranged in order: 3, 7, 8, 8, 9. With 5 values, the median is the 3rd value, which is 8.
Two datasets each have 5 values. Dataset P = {10, 10, 10, 10, 10} and Dataset Q = {6, 8, 10, 12, 14}. Which statement is correct?
Answer: Dataset Q has a larger standard deviation than Dataset P.
Dataset P has all identical values, so its standard deviation is 0. Dataset Q has spread around its mean of 10, giving a standard deviation greater than 0.
The dot plot below shows the number of books read by students over the summer: 1, 2, 2, 3, 4, 4, 4, 5, 6. What is the mean number of books read?
Answer: 3.4
Sum = 1+2+2+3+4+4+4+5+6 = 31; count = 9; mean = 31 ÷ 9 ≈ 3.4.
A dataset has a range of 40, a Q1 of 25, and a Q3 of 55. What is the interquartile range (IQR)?
Answer: 30
IQR = Q3 − Q1 = 55 − 25 = 30.
A data set has a median of 30. If the two largest values are each increased by 50, what happens to the median?
Answer: The median stays the same.
The median depends only on the ordering and the middle value(s); changing extreme values does not move the middle value, so the median remains 30.
A frequency distribution shows that in a class of 30 students, 10 scored 60, 15 scored 80, and 5 scored 100. What is the mean score?
Answer: 76.7
Weighted mean = (10×60 + 15×80 + 5×100) ÷ 30 = (600 + 1200 + 500) ÷ 30 = 2300 ÷ 30 ≈ 76.7.