Spatial Reasoning Flashcards
5 cards from real Bennett Mechanical Test practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.
Read the first 5 Spatial Reasoning flashcards as text
Below is a cube and its net. Determine the letter on the cube's top.
Answer: R
To determine the top letter, visualize folding the 2D net into a 3D cube. If 'Q' is the front face and 'S' is the right face, then 'R' will naturally fold up to become the top face of the cube. 'P' would be the left face, and 'T' the bottom face.
Choose the pair that has the same conditions for dot placement.
Answer: PQ
Analyze the dot placement in each figure to identify the common region it occupies. In figure P, the dot is located exclusively in the overlapping area of the circle and the triangle. Similarly, in figure Q, the dot is also found only in the intersection of the circle and the triangle. Figure R's dot is in the region common to all three shapes (circle, triangle, and square), making its condition different.
How many different routes are there from X to Y if EXACTLY one circle and two triangles must be crossed? (You can only move ALONG THE ARROWS.)
Answer: 5
To find the number of routes, systematically trace all possible paths from X to Y that cross exactly one circle and two triangles. The valid paths are: X-T1-C1-T2-Y, X-T1-C1-T3-Y, X-T1-C2-T2-Y, X-T1-C2-T3-Y, and X-T4-C3-T5-Y. Counting these distinct paths reveals a total of 5 valid routes.
When two similar dice are arranged as shown, the sum of the markings on any pair of opposite faces of any die is 7. What is the sum of the UNSEEN faces in the diagram?"
Answer: 24
To find the sum of the visible faces, identify the numbers shown on each die. For the left die, the visible faces are 5 (top), 3 (front), and 1 (right). For the right die, the visible faces are 5 (top), 6 (front), and 4 (right). Adding these numbers together (5 + 3 + 1 + 5 + 6 + 4) yields a total sum of 24.
What is the table's height?
Answer: 150
Let T be the table's height, C be the cat's height, and D be the dog's height. From the first diagram, we have T + C - D = 170. From the second diagram, we have T + D - C = 130. Adding these two equations together (2T + C - D + D - C = 170 + 130) simplifies to 2T = 300, which means the table's height (T) is 150.