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Maintenance Technician: Math Ohm's Law Flashcards

6 cards from real Amazon practice questions. Tap to flip, then mark Knew It or Still Learning — missed cards come back until you master them.

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  1. Two resistors of 6Ω and 12Ω are connected in parallel. What is the equivalent resistance?

    Answer: 4Ω

    1/R = 1/6 + 1/12 = 2/12 + 1/12 = 3/12 → R = 4Ω.

  2. If current doubles while resistance stays constant, what happens to power dissipated in the resistor?

    Answer: Power quadruples

    P = I²R. If I doubles, I² quadruples, so power quadruples.

  3. A 120V circuit has a fuse rated at 10A. What is the minimum resistance that prevents the fuse from blowing?

    Answer: 12Ω

    R_min = V ÷ I_max = 120 ÷ 10 = 12Ω. Any resistance below 12Ω would draw more than 10A and blow the fuse.

  4. A circuit operates at 240V with 8A. The power factor is 0.8. What is the true (real) power?

    Answer: 1,536W

    True power = V × I × PF = 240 × 8 × 0.8 = 1,536W.

  5. A conveyor motor has a resistance of 8Ω. It is connected to a 48V supply. How much heat energy (in joules) does it produce in 10 seconds?

    Answer: 2,880J

    I = V/R = 48/8 = 6A. P = I²R = 36×8 = 288W. Energy = P×t = 288×10 = 2,880J.

  6. What happens to current in a circuit if resistance is halved while voltage stays constant?

    Answer: Current doubles

    I = V/R. If R is halved (R/2), then I = V/(R/2) = 2V/R = 2I — current doubles.