PERT Algebraic Concepts & Applications 3 — Questions and Answers
Question 1: Solve for y: y/3 + 4 = 10.
- y = 18 (Correct answer)
- y = 2
- y = 42
- y = 6
Correct answer: y = 18
Subtract 4 to get y/3 = 6, then multiply by 3 to get y = 18.
Question 2: Expand: (x + 5)(x - 2).
- x² + 3x - 10 (Correct answer)
- x² - 3x - 10
- x² + 3x + 10
- x² + 7x - 10
Correct answer: x² + 3x - 10
Using FOIL: x² - 2x + 5x - 10 = x² + 3x - 10.
Question 3: A rectangle has length 2x and width x + 3. What is its perimeter in terms of x?
- 6x + 6 (Correct answer)
- 2x² + 6x
- 3x + 3
- 6x + 3
Correct answer: 6x + 6
Perimeter = 2(2x) + 2(x + 3) = 4x + 2x + 6 = 6x + 6.
Question 4: Solve for x: x² = 49.
- x = ±7 (Correct answer)
- x = 7
- x = 24.5
- x = ±24.5
Correct answer: x = ±7
Taking the square root of both sides gives x = 7 or x = -7.
Question 5: Simplify: (12x⁵)/(4x²).
- 3x³ (Correct answer)
- 3x⁷
- 8x³
- 3x²·⁵
Correct answer: 3x³
Divide coefficients (12/4 = 3) and subtract exponents (5 - 2 = 3) for 3x³.
Question 6: If 5(x - 2) = 3x + 4, what is x?
- x = 7 (Correct answer)
- x = -7
- x = 3
- x = 1
Correct answer: x = 7
5x - 10 = 3x + 4 gives 2x = 14, so x = 7.
Question 7: What is the value of the expression 3a + 2b when a = 4 and b = -3?
- 6 (Correct answer)
- 18
- -6
- 12
Correct answer: 6
3(4) + 2(-3) = 12 - 6 = 6.
PERT Algebraic Concepts & Applications 3
Solve for y: y/3 + 4 = 10.