Mettl Quantitative Aptitude 2 — Questions and Answers

Question 1: A train travels 360 km in 4 hours. If it increases its speed by 20%, how long will it take to travel the same distance?

3 hours 10 minutes
3 hours 20 minutes (Correct answer)
3 hours 30 minutes
2 hours 50 minutes

Correct answer: 3 hours 20 minutes

Original speed = 360/4 = 90 km/h. New speed = 90 × 1.20 = 108 km/h. Time = 360/108 = 3.33 hours = 3 hours 20 minutes.

This problem tests speed-distance-time relationships. First, find the original speed: 360 km ÷ 4 hours = 90 km/h. A 20% increase gives a new speed of 90 × 1.20 = 108 km/h. Then, time = distance ÷ speed = 360 ÷ 108 = 10/3 hours = 3 hours and 20 minutes. Mettl quantitative tests frequently include these motion problems.

Question 2: The ratio of boys to girls in a class is 3:2. If there are 30 students in total, how many are girls?

10
12 (Correct answer)
18
15

Correct answer: 12

Total ratio parts = 3+2 = 5. Girls = (2/5) × 30 = 12.

In ratio problems, the ratio 3:2 means for every 5 students, 3 are boys and 2 are girls. With 30 total students: boys = (3/5) × 30 = 18, girls = (2/5) × 30 = 12. Always verify: 18 + 12 = 30. Ratio problems are a staple of Mettl aptitude assessments.

Question 3: What is the compound interest on ₹5000 at 10% per annum for 2 years?

₹1000
₹1050 (Correct answer)
₹1100
₹950

Correct answer: ₹1050

CI = P(1+r)^t - P = 5000(1.1)^2 - 5000 = 5000(1.21) - 5000 = 6050 - 5000 = ₹1050.

Compound interest differs from simple interest in that interest is earned on previously accumulated interest. Formula: A = P(1 + r/100)^n. Here, A = 5000 × (1.10)^2 = 5000 × 1.21 = 6050. CI = 6050 - 5000 = ₹1050. Compare with simple interest: 5000 × 10% × 2 = ₹1000. The difference of ₹50 is the 'interest on interest.'

Question 4: If 8 men can complete a piece of work in 20 days, how many days will 10 men take to complete the same work?

14 days
16 days (Correct answer)
18 days
25 days

Correct answer: 16 days

Total work = 8 × 20 = 160 man-days. Days for 10 men = 160/10 = 16 days.

Work problems use the concept of 'man-days.' Total work = 8 men × 20 days = 160 man-days. With 10 men, days required = 160 ÷ 10 = 16 days. Notice that more men means fewer days (inverse relationship). This type of problem tests your ability to apply proportional reasoning, a key skill in Mettl quantitative sections.

Question 5: A shopkeeper marks up his goods by 40% and then offers a 20% discount. What is his net profit percentage?

20%
12% (Correct answer)
14%
10%

Correct answer: 12%

Let CP = 100. MP = 140. SP = 140 × 0.80 = 112. Profit% = (112-100)/100 × 100 = 12%.

Markup and discount problems are common in Mettl tests. Starting with cost price (CP) = 100: Marked Price (MP) = 100 × 1.40 = 140. After 20% discount, Selling Price (SP) = 140 × (1 - 0.20) = 140 × 0.80 = 112. Net Profit = SP - CP = 112 - 100 = 12. Profit % = 12%. Important: markup and discount do not cancel each other out because they apply to different bases.

Question 6: The average of five consecutive even numbers is 20. What is the smallest number in the sequence?

14
16 (Correct answer)
18
12

Correct answer: 16

For 5 consecutive even numbers, the middle (3rd) number equals the average = 20. So the numbers are 16, 18, 20, 22, 24. Smallest = 16.

For any arithmetic sequence with an odd number of terms, the average equals the middle term. With 5 consecutive even numbers and average = 20, the middle (3rd) term = 20. Going backwards by 2 each step: 20, 18, 16 — so the sequence is 16, 18, 20, 22, 24. The smallest is 16. Verify: (16+18+20+22+24)/5 = 100/5 = 20. ✓

Mettl Quantitative Aptitude 2

A train travels 360 km in 4 hours.
If it increases its speed by 20%, how long will it take to travel the same distance?