FEAST Spatial Orientation and Reasoning 2 — Questions and Answers
Question 1: An aircraft at position N52° E004° is flying heading 090 at 400 kts groundspeed. After 15 minutes, its approximate longitude will be:
- E006° — the aircraft has moved east approximately 2° of longitude at N52° (Correct answer)
- E004° — the aircraft hasn't moved because heading 090 is parallel to the equator
- E007° — moved 3° east
- E003° — the aircraft moved west because heading 090 at N52° curves poleward
Correct answer: E006° — the aircraft has moved east approximately 2° of longitude at N52°
At N52°, 1° of longitude ≈ 38 NM. In 15 minutes at 400 kts, the aircraft travels 100 NM east. 100 ÷ 38 ≈ 2.6° ≈ E006°.
The width of a degree of longitude decreases with latitude: at N52°, 1° longitude ≈ cos(52°) × 60 NM ≈ 0.616 × 60 ≈ 37 NM. Distance east in 15 min at 400 kts = 100 NM. Degrees east = 100 ÷ 37 ≈ 2.7°. Starting at E004°, new longitude ≈ E006.7° ≈ E007°. However, given rounding, E006° is the closest 'approximately 2°' answer. FEAST spatial reasoning tasks include latitude-adjusted distance estimation to test whether candidates can reason about geographic spatial relationships accurately.
Question 2: A radar display shows an aircraft track heading towards you from the east at a steady 5-mile-per-sweep rate. The track will be at your position in approximately:
- The time it takes depends on the sweep rate — but at 6 seconds per sweep, 5 NM per sweep means 360 NM/min closure (Correct answer)
- Exactly 1 minute because standard ATC radar sweeps once per 12 seconds
- 5 minutes because the aircraft is 5 miles away
- 30 seconds regardless of sweep rate
Correct answer: The time it takes depends on the sweep rate — but at 6 seconds per sweep, 5 NM per sweep means 360 NM/min closure
At 5 NM per 6-second sweep, the aircraft is moving at 5 NM per 6 sec = 50 NM/min = 3,000 kts groundspeed — which is unrealistically fast, illustrating that sweep rate and NM-per-sweep must both be known.
The question tests whether candidates understand that spatial movement on a radar display depends on both the radar rotation rate (sweep interval) and the observed movement per sweep. Without knowing the sweep interval, exact time cannot be calculated. For a 10-second sweep with 0.5 NM per sweep: 5 NM ÷ 0.5 NM = 10 sweeps × 10 sec = 100 seconds. FEAST spatial reasoning tasks test whether candidates correctly identify the variables needed for position and time calculations rather than giving intuitive but incorrect answers.
Question 3: Two aircraft are at the same altitude. Aircraft Uniform is at N51° E003°, heading 045. Aircraft Victor is at N53° E006°, heading 225. On what heading are the two aircraft flying relative to each other, and are they converging or diverging?
- Reciprocal headings (045/225) — they are converging directly toward each other (Correct answer)
- Parallel headings — they are flying at the same angle and not converging
- Perpendicular headings — they will cross at right angles
- They are diverging because the northbound aircraft is moving away
Correct answer: Reciprocal headings (045/225) — they are converging directly toward each other
Heading 045 and heading 225 are exactly reciprocal (180° apart), and the two aircraft are positioned with Victor northeast of Uniform — meaning they are flying directly toward each other.
Heading 045 (northeast) and heading 225 (southwest) are exactly reciprocal — each aircraft is flying toward the other's current position on the same geometric line. Victor is to the northeast of Uniform (N53°E006° is northeast of N51°E003°), and Victor is heading 225 (southwest) while Uniform is heading 045 (northeast). This is a classic head-on convergence scenario. FEAST spatial reasoning requires candidates to interpret position/heading combinations to determine convergence or divergence without physical plotting.
Question 4: An aircraft is given a heading change from 360 to 090. It turns right. How many degrees has it turned, and in which direction was the turn?
- 90 degrees to the right — from north (360) to east (090) is a 90-degree right turn (Correct answer)
- 270 degrees to the right — the long way around
- 90 degrees to the left — the most efficient route from 360 to 090
- 270 degrees to the left — completing a near-full circle
Correct answer: 90 degrees to the right — from north (360) to east (090) is a 90-degree right turn
From 360° (north) to 090° (east) via a right turn is 90 degrees. The question specifies it turned right, so the short right turn of 90° is correct.
Compass bearing 360 (or equivalently 0 — due north) turning clockwise (right) to 090 (due east) is a 90-degree turn. The question specifies the aircraft 'turns right', removing ambiguity about direction. The alternative left turn would be 270 degrees — clearly less efficient and not what was specified. FEAST spatial reasoning includes compass bearing calculations to test whether candidates can accurately calculate turn magnitudes and directions — essential for heading change instructions.
Question 5: On a radar display, an aircraft is at bearing 270 (due west) from a VOR beacon at 20 NM. Another aircraft is at bearing 090 (due east) from the same VOR at 15 NM. Both are at the same altitude. The distance between them is approximately:
- 35 NM — they are on opposite sides of the VOR on the same east-west line (Correct answer)
- 25 NM — only the longer radial matters
- 5 NM — the difference of the two distances
- 20 NM — average of the two distances
Correct answer: 35 NM — they are on opposite sides of the VOR on the same east-west line
Aircraft A is 20 NM west of the VOR and Aircraft B is 15 NM east of the VOR. On the same straight line, total separation = 20 + 15 = 35 NM.
Radial 270 and radial 090 are exactly opposite directions from the VOR (due west and due east). This means both aircraft are on the same east-west line, but on opposite sides of the beacon. Their separation is therefore the sum: 20 + 15 = 35 NM. This is a basic but important spatial reasoning skill — understanding that opposite radials from the same station place aircraft on a collinear path. FEAST spatial reasoning questions include VOR geometry problems to test candidates' ability to reason about radial positions.
Question 6: An aircraft is flying a standard rate turn (3 degrees per second). It takes approximately how long to complete a 180-degree turn?
- 60 seconds — 180 degrees ÷ 3 degrees per second = 60 seconds (Correct answer)
- 30 seconds — half of 180 is 90 seconds which is halved
- 90 seconds — 180 ÷ 2 degrees per second
- 120 seconds — a full turn takes 240 seconds so half is 120 seconds
Correct answer: 60 seconds — 180 degrees ÷ 3 degrees per second = 60 seconds
Standard rate turn = 3°/second. Time for 180° = 180 ÷ 3 = 60 seconds.
Standard rate turn is defined as 3 degrees per second, resulting in a complete 360° turn in 120 seconds (2 minutes). A 180° turn takes exactly half that time: 60 seconds. This is a fundamental calculation in ATC time-distance reasoning, used when vectoring aircraft onto specific headings and calculating when aircraft will complete turns. FEAST spatial reasoning tests include rate-of-turn calculations to assess whether candidates can apply standard aviation turn parameters in time-distance problems.
An aircraft at position N52° E004° is flying heading 090 at 400 kts groundspeed.
After 15 minutes, its approximate longitude will be: