FEAST ATC Multitasking Simulation Questions and Answers 1 — Questions and Answers
Question 1: Flight progress strips are sorted by a two-level rule: 1. Primary: Destination airport code, sorted alphabetically (A-Z). 2. Secondary: Callsign, sorted numerically by the flight number (lowest to highest). Given the already sorted list below, where should the new flight strip for 'KLM448 to EDDF' be inserted? - Position 1 - AFR912 to EDDF - Position 2 - BAW235 to EGLL - Position 3 - BAW771 to EGLL - Position 4
- Position 1 (Correct answer)
- Position 2
- Position 3
- Position 4
Correct answer: Position 1
The primary sorting rule is by destination. The new strip's destination is EDDF, which comes alphabetically before EGLL. Therefore, it must be placed before the BAW flights. The secondary rule applies to flights with the same destination. Comparing KLM448 to AFR912 (both going to EDDF), we sort by the flight number. 448 is lower than 912, so KLM448 must be placed before AFR912. The correct location is Position 1.
Question 2: You are monitoring four aircraft on the same airway. Standard vertical separation is 1000 feet. The current flight levels are: - RYR11: FL380 - EZY22: FL360 - WIZ33: FL350 - AFR44: FL330 Which of the following instructions creates an immediate conflict (loss of separation)?
- Instruct RYR11 to descend to FL370.
- Instruct WIZ33 to climb to FL360. (Correct answer)
- Instruct AFR44 to climb to FL340.
- Instruct EZY22 to descend to FL350.
Correct answer: Instruct WIZ33 to climb to FL360.
If WIZ33, currently at FL350, is instructed to climb to FL360, it will be at the same altitude as EZY22, which is already at FL360. This eliminates the required 1000 feet vertical separation and creates an immediate conflict.
Question 3: From an aircraft's perspective, its nose is pointing straight ahead (12 o'clock). Another aircraft is located at its 4 o'clock position. To fly directly towards the second aircraft, the pilot would need to make a turn of approximately:
- 90 degrees to the left
- 45 degrees to the right
- 120 degrees to the right (Correct answer)
- 180 degrees
Correct answer: 120 degrees to the right
On a clock face, there are 360 degrees. With 12 hours, each hour mark represents 30 degrees (360 / 12 = 30). The 4 o'clock position is 4 hour-marks away from the 12 o'clock position (straight ahead). Therefore, the required turn is 4 * 30 = 120 degrees. Since 4 o'clock is to the right of 12 o'clock, it is a 120-degree turn to the right.
Question 4: An automated system assigns a 4-digit temporary identifier to aircraft based on their assigned flight level (FL). The rule is: The three digits of the FL are reversed, and then the number 2 is added to each individual digit. The final identifier is this new 3-digit number followed by a 0. Which identifier corresponds to an aircraft assigned FL350?
- 5720
- 2750 (Correct answer)
- 0532
- 3502
Correct answer: 2750
Following the rule for FL350: 1. The digits are 3, 5, 0. 2. Reverse the digits: 0, 5, 3. 3. Add 2 to each digit: (0+2), (5+2), (3+2) which results in 2, 7, 5. 4. The new number is 275. 5. Append a 0 to get the final identifier: 2750.
Question 5: Four aircraft (A, B, C, D) must be assigned final flight levels from the set {FL250, FL260, FL270, FL280}. The assignments must follow these rules: 1. Aircraft A must be higher than Aircraft B. 2. Aircraft C must be at the lowest available level. 3. Aircraft D cannot be at a level adjacent to Aircraft A. What is the correct flight level for Aircraft D?
- FL250
- FL280
- FL260 (Correct answer)
- FL270
Correct answer: FL260
1. From Rule 2, Aircraft C is assigned FL250. 2. This leaves FL260, FL270, and FL280 for A, B, and D. 3. From Rule 1, A must be higher than B. 4. From Rule 3, D cannot be next to A. If A is at FL280, D cannot be at FL270. This forces D to be at FL260, and B takes the remaining FL270. This configuration (A=280, B=270, D=260) satisfies all rules. If A were at FL270, D would have to be at FL280 (not adjacent), but then B would be at FL260, which works. However, the first scenario is also valid. Let's recheck. Ah, if A=280, B=270, then D must be at FL260. Not adjacent. This works. If A=280, B=260, then D must be at FL270. Adjacent. Invalid. If A=270, B=260, then D must be at FL280. Not adjacent. This works. Let's re-read. The question has one unique solution. Let's re-evaluate. A>B. C=FL250. D not adjacent to A. Try assigning A. If A=FL280, D cannot be FL270. D must be FL260. This leaves B=FL270. A(280)>B(270) is true. This is a valid solution. If A=FL270, D cannot be FL260 or FL280. No level for D. Invalid. Therefore, the only solution is A=FL280, B=FL270, C=FL250, and D=FL260.
Question 6: You are monitoring four aircraft on a grid. Their current positions (X,Y) and velocities (Vx, Vy) per minute are listed below. Which two aircraft are on a direct collision course if they maintain their current velocity? - Aircraft A: Position (20, 60), Velocity (10, 0) - Aircraft B: Position (60, 100), Velocity (0, -10) - Aircraft C: Position (80, 70), Velocity (-10, 0) - Aircraft D: Position (50, 20), Velocity (0, 10)
- Aircraft A and C
- Aircraft B and D
- Aircraft A and B (Correct answer)
- Aircraft C and D
Correct answer: Aircraft A and B
Aircraft A is flying right along the line Y=60. Aircraft B is flying down along the line X=60. Their paths will intersect at coordinate (60, 60). To check for a collision, we calculate the time for each to reach the intersection. Time for A: (60-20) / 10 = 4 minutes. Time for B: (100-60) / 10 = 4 minutes. Since they both reach the intersection point (60, 60) at the same time (4 minutes), they are on a collision course.
FEAST ATC Multitasking Simulation Questions and Answers 1
Flight progress strips are sorted by a two-level rule:
1.
Primary: Destination airport code, sorted alphabetically (A-Z).
2.
Secondary: Callsign, sorted numerically by the flight number (lowest to highest).
Given the already sorted list below, where should the new flight strip for 'KLM448 to EDDF' be inserted?
- Position 1
- AFR912 to EDDF
- Position 2
- BAW235 to EGLL
- Position 3
- BAW771 to EGLL
- Position 4