CCST IP Addressing & Subnetting 4 — Questions and Answers
Question 1: A technician sees the IP address 192.168.1.255 on a /24 network. What is this address?
- Broadcast address (Correct answer)
- Network address
- Gateway address
- Loopback address
Correct answer: Broadcast address
The last address in any subnet (all host bits set to 1) is the directed broadcast address for that network.
Question 2: What is the total number of IPv4 addresses in a /22 subnet?
- 1024 (Correct answer)
- 512
- 2048
- 256
Correct answer: 1024
A /22 leaves 10 host bits, so 2^10 = 1024 total addresses.
Question 3: Which command on a Cisco device shows the IP address and subnet mask configured on an interface?
- show ip interface brief (Correct answer)
- show running-config interface
- show interfaces status
- show ip route
Correct answer: show ip interface brief
The 'show ip interface brief' command displays IP addresses and status for all interfaces in a concise format.
Question 4: A host with IP 192.168.10.50/28 tries to communicate with 192.168.10.65. Are these hosts on the same subnet?
- No, they are on different subnets (Correct answer)
- Yes, they are on the same subnet
- It depends on the default gateway
- Cannot be determined without the MAC address
Correct answer: No, they are on different subnets
/28 creates 16-address blocks; .50 belongs to 192.168.10.48–.63 and .65 belongs to 192.168.10.64–.79, so they are on different subnets.
Question 5: What does VLSM (Variable Length Subnet Masking) allow network engineers to do?
- Use different subnet mask sizes within the same network to minimize IP address waste (Correct answer)
- Assign multiple IP addresses to a single interface
- Automatically allocate IP addresses using DHCP
- Combine multiple subnets into one larger network
Correct answer: Use different subnet mask sizes within the same network to minimize IP address waste
VLSM allows subnets of different sizes within the same address space, allocating exactly as many addresses as each segment needs.
Question 6: Which of the following correctly describes a /16 subnet mask?
- 255.255.0.0 with 65,534 usable hosts (Correct answer)
- 255.255.0.0 with 65,536 usable hosts
- 255.255.255.0 with 254 usable hosts
- 255.0.0.0 with 16,777,214 usable hosts
Correct answer: 255.255.0.0 with 65,534 usable hosts
A /16 mask is 255.255.0.0, providing 2^16 = 65,536 total addresses minus 2 = 65,534 usable hosts.
Question 7: What is the first usable host address in the subnet 172.20.0.0/20?
- 172.20.0.1 (Correct answer)
- 172.20.0.0
- 172.20.1.0
- 172.20.0.2
Correct answer: 172.20.0.1
The network address is 172.20.0.0, so the first usable host is 172.20.0.1.
A technician sees the IP address 192.168.1.255 on a /24 network.
What is this address?