AMC12 Complex Numbers 1 — Questions and Answers
Question 1: If z = 3 + 4i, what is |z|, the modulus of z?
- 5 (Correct answer)
- 7
- 25
- 4
Correct answer: 5
The modulus is √(3² + 4²) = √(9 + 16) = √25 = 5.
Question 2: What is the product (2 + 3i)(1 − 2i)?
- 2 − i
- 8 − i (Correct answer)
- −4 + 7i
- 8 + i
Correct answer: 8 − i
Expanding: 2 − 4i + 3i − 6i² = 2 − i + 6 = 8 − i, since i² = −1.
Question 3: What is i^23?
- 1
- i
- −1
- −i (Correct answer)
Correct answer: −i
Since i repeats with period 4 and 23 ≡ 3 (mod 4), i^23 = i^3 = −i.
Question 4: If z = 1 + i, what is z^4?
- 4
- −4 (Correct answer)
- 4i
- −4i
Correct answer: −4
z² = (1+i)² = 2i, so z⁴ = (2i)² = 4i² = −4.
Question 5: What is the real part of (3 + 4i) / (1 + 2i)?
- 3/5
- 11/5 (Correct answer)
- −1/5
- 2
Correct answer: 11/5
Multiply numerator and denominator by the conjugate (1−2i): (3+4i)(1−2i)/5 = (11−2i)/5, giving real part 11/5.
Question 6: If z₁ = 1 + 2i and z₂ = 2 − i, what is z₁ + z₂?
- 3 + i (Correct answer)
- 3 − i
- −1 + 3i
- 1 + 3i
Correct answer: 3 + i
Add real and imaginary parts separately: (1+2) + (2−1)i = 3 + i.
Question 7: If z = cos(π/6) + i·sin(π/6), what is z + z̄ (z plus its complex conjugate)?
- 0
- 1
- √3 (Correct answer)
- 2
Correct answer: √3
z = √3/2 + i/2 and z̄ = √3/2 − i/2, so z + z̄ = √3 (the imaginary parts cancel).
If z = 3 + 4i, what is |z|, the modulus of z?